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2/3(5x+35)-8=12
We move all terms to the left:
2/3(5x+35)-8-(12)=0
Domain of the equation: 3(5x+35)!=0We add all the numbers together, and all the variables
x∈R
2/3(5x+35)-20=0
We multiply all the terms by the denominator
-20*3(5x+35)+2=0
Wy multiply elements
-60x(5+2=0
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