2/3(5x-2)-7(10-5x)=1/7(2x+9)

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Solution for 2/3(5x-2)-7(10-5x)=1/7(2x+9) equation:



2/3(5x-2)-7(10-5x)=1/7(2x+9)
We move all terms to the left:
2/3(5x-2)-7(10-5x)-(1/7(2x+9))=0
Domain of the equation: 3(5x-2)!=0
x∈R
Domain of the equation: 7(2x+9))!=0
x∈R
We add all the numbers together, and all the variables
2/3(5x-2)-7(-5x+10)-(1/7(2x+9))=0
We multiply parentheses
2/3(5x-2)+35x-(1/7(2x+9))-70=0
We calculate fractions
35x+(14x2/(3(5x-2)*7(2x+9)))+(-3x5/(3(5x-2)*7(2x+9)))-70=0
We calculate terms in parentheses: +(14x2/(3(5x-2)*7(2x+9))), so:
14x2/(3(5x-2)*7(2x+9))
We multiply all the terms by the denominator
14x2
We add all the numbers together, and all the variables
14x^2
Back to the equation:
+(14x^2)
We calculate terms in parentheses: +(-3x5/(3(5x-2)*7(2x+9))), so:
-3x5/(3(5x-2)*7(2x+9))
We multiply all the terms by the denominator
-3x5
We add all the numbers together, and all the variables
-3x^5
We do not support expression: x^5

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