2/3(5x-3)+7x=17/3

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Solution for 2/3(5x-3)+7x=17/3 equation: 



2/3(5x-3)+7x=17/3

We move all terms to the left:

2/3(5x-3)+7x-(17/3)=0



Domain of the equation: 3(5x-3)!=0

x∈R



We add all the numbers together, and all the variables

2/3(5x-3)+7x-(+17/3)=0

We add all the numbers together, and all the variables

7x+2/3(5x-3)-(+17/3)=0

We get rid of parentheses

7x+2/3(5x-3)-17/3=0

We calculate fractions


7x=0

x=0/7

x=0

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