2/3(6(-3x))=(1-x)+(3-x)

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Solution for 2/3(6(-3x))=(1-x)+(3-x) equation: 



2/3(6(-3x))=(1-x)+(3-x)

We move all terms to the left:

2/3(6(-3x))-((1-x)+(3-x))=0



Domain of the equation: 3(6(-3x))!=0

x∈R



We add all the numbers together, and all the variables

2/3(6(-3x))-((-1x+1)+(-1x+3))=0

We multiply all the terms by the denominator


-(((-1x+1)+(-1x+3)))*3(6(-3x))+2=0



We calculate terms in parentheses: -(((-1x+1)+(-1x+3)))*3(6(-3x)), so:

((-1x+1)+(-1x+3)))*3(6(-3x)



We calculate terms in parentheses: +((-1x+1)+(-1x+3)))*3(6(-3x), so:

(-1x+1)+(-1x+3)))*3(6(-3x

We add all the numbers together, and all the variables

-3x+(-1x+1)+(-1x+3)))*3(6(

We get rid of parentheses

-3x-1x+(-1x+3)))*3(6(+1

We add all the numbers together, and all the variables

-4x+(-1x+3)))*3(6(+1

Back to the equation:

+(-4x+(-1x+3)))*3(6(+1)



We add all the numbers together, and all the variables

(-4x+(-1x+3)))*3(61

Back to the equation:

-((-4x+(-1x+3)))*3(61)



We move all terms containing x to the left, all other terms to the right

-((-4x+(-1x+3)))*361=-2

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