2/3(6-3x)=(1-x)+(3-x)

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Solution for 2/3(6-3x)=(1-x)+(3-x) equation: 


x in (-oo:+oo)

(2/3)*(6-(3*x)) = 1-x-x+3 // - 1-x-x+3

(2/3)*(6-(3*x))+x+x-3-1 = 0

(2/3)*(6-3*x)+x+x-3-1 = 0

2/3*(6-3*x)+x+x-3-1 = 0

2/3*(6-3*x)+x+x-3-1 = 0

x-x-3-1+4 = 0

4-3-1 = 0

1-1 = 0

0 = 0

0 = 0

x belongs to the empty set

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