2/3(6-3x)=(1-x)=(3-x)

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Solution for 2/3(6-3x)=(1-x)=(3-x) equation: 



2/3(6-3x)=(1-x)=(3-x)

We move all terms to the left:

2/3(6-3x)-((1-x))=0



Domain of the equation: 3(6-3x)!=0

x∈R



We add all the numbers together, and all the variables

2/3(-3x+6)-((-1x+1))=0

We multiply all the terms by the denominator


-(((-1x+1)))*3(-3x+6)+2=0



We calculate terms in parentheses: -(((-1x+1)))*3(-3x+6), so:

((-1x+1)))*3(-3x+6

We add all the numbers together, and all the variables

-3x+((-1x+1)))*3(+6

Back to the equation:

-(-3x+((-1x+1)))*3(+6)



We add all the numbers together, and all the variables

-(-3x+((-1x+1)))*36+2=0

We move all terms containing x to the left, all other terms to the right

-(-3x+((-1x+1)))*36=-2

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