2/3(6a+3b)-1/2(a-2b)

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Solution for 2/3(6a+3b)-1/2(a-2b) equation: 


x in (-oo:+oo)

(2/3)*(6*a+3*b)-((1/2)*(a-(2*b))) = 0

(2/3)*(6*a+3*b)+(-1/2)*(a-2*b) = 0

2/3*(6*a+3*b)-1/2*(a-2*b) = 0

2/3*(6*a+3*b)-1/2*(a-2*b) = 0

7/2*a+3*b = 0

7/2*a+3*b = 0

x belongs to the empty set

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