2/3(6c-18)+3/4((8c+34)=-18

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Solution for 2/3(6c-18)+3/4((8c+34)=-18 equation: 



2/3(6c-18)+3/4((8c+34)=-18

We move all terms to the left:

2/3(6c-18)+3/4((8c+34)-(-18)=0



Domain of the equation: 3(6c-18)!=0

c∈R





Domain of the equation: 4((8c+34)-(-18)!=0

c∈R



We calculate fractions


(8c(()/(3(6c-18)*4((8c+34)-(-18))+(9c6/(3(6c-18)*4((8c+34)-(-18))=0



We calculate terms in parentheses: +(8c(()/(3(6c-18)*4((8c+34)-(-18))+(9c6/(3(6c-18)*4((8c+34)-(-18)), so:

8c(()/(3(6c-18)*4((8c+34)-(-18))+(9c6/(3(6c-18)*4((8c+34)-(-18)

We can not solve this equation

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