2/3(6k+12)+10k=3k-47

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Solution for 2/3(6k+12)+10k=3k-47 equation: 



2/3(6k+12)+10k=3k-47

We move all terms to the left:

2/3(6k+12)+10k-(3k-47)=0



Domain of the equation: 3(6k+12)!=0

k∈R



We add all the numbers together, and all the variables

10k+2/3(6k+12)-(3k-47)=0

We get rid of parentheses

10k+2/3(6k+12)-3k+47=0

We multiply all the terms by the denominator


10k*3(6k+12)-3k*3(6k+12)+47*3(6k+12)+2=0

Wy multiply elements

30k^2(6-9k^2(6+141k(6+2=0

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