2/3(6m-12)=-17

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Solution for 2/3(6m-12)=-17 equation: 



2/3(6m-12)=-17

We move all terms to the left:

2/3(6m-12)-(-17)=0



Domain of the equation: 3(6m-12)!=0

m∈R



We add all the numbers together, and all the variables

2/3(6m-12)+17=0

We multiply all the terms by the denominator


17*3(6m-12)+2=0

Wy multiply elements

51m(6+2=0

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