2/3(6m-3)=-17-m

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Solution for 2/3(6m-3)=-17-m equation: 



2/3(6m-3)=-17-m

We move all terms to the left:

2/3(6m-3)-(-17-m)=0



Domain of the equation: 3(6m-3)!=0

m∈R



We add all the numbers together, and all the variables

2/3(6m-3)-(-1m-17)=0

We get rid of parentheses

2/3(6m-3)+1m+17=0

We multiply all the terms by the denominator


1m*3(6m-3)+17*3(6m-3)+2=0

Wy multiply elements

3m^2(6+51m(6+2=0

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