2/3(6w-24)=4/5(10w+15)

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Solution for 2/3(6w-24)=4/5(10w+15) equation:



2/3(6w-24)=4/5(10w+15)
We move all terms to the left:
2/3(6w-24)-(4/5(10w+15))=0
Domain of the equation: 3(6w-24)!=0
w∈R
Domain of the equation: 5(10w+15))!=0
w∈R
We calculate fractions
(10w1/(3(6w-24)*5(10w+15)))+(-12w6/(3(6w-24)*5(10w+15)))=0
We calculate terms in parentheses: +(10w1/(3(6w-24)*5(10w+15))), so:
10w1/(3(6w-24)*5(10w+15))
We multiply all the terms by the denominator
10w1
We add all the numbers together, and all the variables
10w
Back to the equation:
+(10w)
We calculate terms in parentheses: +(-12w6/(3(6w-24)*5(10w+15))), so:
-12w6/(3(6w-24)*5(10w+15))
We multiply all the terms by the denominator
-12w6
We add all the numbers together, and all the variables
-12w^6
We do not support ewpression: w^6

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