2/3(6x+1)=6+1/3(12x+8)

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Solution for 2/3(6x+1)=6+1/3(12x+8) equation: 



2/3(6x+1)=6+1/3(12x+8)

We move all terms to the left:

2/3(6x+1)-(6+1/3(12x+8))=0



Domain of the equation: 3(6x+1)!=0

x∈R





Domain of the equation: 3(12x+8))!=0

x∈R



We calculate fractions


(6x1/(3(6x+1)*3(12x+8)))+(-3x6/(3(6x+1)*3(12x+8)))=0



We calculate terms in parentheses: +(6x1/(3(6x+1)*3(12x+8))), so:

6x1/(3(6x+1)*3(12x+8))

We multiply all the terms by the denominator


6x1

We add all the numbers together, and all the variables

6x

Back to the equation:

+(6x)





We calculate terms in parentheses: +(-3x6/(3(6x+1)*3(12x+8))), so:

-3x6/(3(6x+1)*3(12x+8))

We multiply all the terms by the denominator


-3x6

We add all the numbers together, and all the variables

-3x^6

We do not support expression: x^6

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