2/3(6x+12)=1/2(4x+8)

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Solution for 2/3(6x+12)=1/2(4x+8) equation: 



2/3(6x+12)=1/2(4x+8)

We move all terms to the left:

2/3(6x+12)-(1/2(4x+8))=0



Domain of the equation: 3(6x+12)!=0

x∈R





Domain of the equation: 2(4x+8))!=0

x∈R



We calculate fractions


(4x4/(3(6x+12)*2(4x+8)))+(-3x6/(3(6x+12)*2(4x+8)))=0



We calculate terms in parentheses: +(4x4/(3(6x+12)*2(4x+8))), so:

4x4/(3(6x+12)*2(4x+8))

We multiply all the terms by the denominator


4x4

We add all the numbers together, and all the variables

4x^4

We do not support expression: x^4

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