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2/3(6x+12)=5x-20
We move all terms to the left:
2/3(6x+12)-(5x-20)=0
Domain of the equation: 3(6x+12)!=0We get rid of parentheses
x∈R
2/3(6x+12)-5x+20=0
We multiply all the terms by the denominator
-5x*3(6x+12)+20*3(6x+12)+2=0
Wy multiply elements
-15x^2(6+60x(6+2=0
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