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2/3(6x+3)=1/3(2+4x)
We move all terms to the left:
2/3(6x+3)-(1/3(2+4x))=0
Domain of the equation: 3(6x+3)!=0
x∈R
Domain of the equation: 3(2+4x))!=0We add all the numbers together, and all the variables
x∈R
2/3(6x+3)-(1/3(4x+2))=0
We calculate fractions
(6x4/(3(6x+3)*3(4x+2)))+(-3x6/(3(6x+3)*3(4x+2)))=0
We calculate terms in parentheses: +(6x4/(3(6x+3)*3(4x+2))), so:
6x4/(3(6x+3)*3(4x+2))
We multiply all the terms by the denominator
6x4
We add all the numbers together, and all the variables
6x^4
We do not support expression: x^4
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