2/3(6x+3)=8x+2-4x

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Solution for 2/3(6x+3)=8x+2-4x equation: 


x in (-oo:+oo)

(2/3)*(6*x+3) = 8*x-(4*x)+2 // - 8*x-(4*x)+2

(2/3)*(6*x+3)-(8*x)+4*x-2 = 0

(2/3)*(6*x+3)-8*x+4*x-2 = 0

2/3*(6*x+3)-8*x+4*x-2 = 0

2/3*(6*x+3)-8*x+4*x-2 = 0

4*x-4*x-2+2 = 0

2-2 = 0

0 = 0

0 = 0

x belongs to the empty set

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