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(2/3)*(6*x+30) = 5*(x+5)+x-x // - 5*(x+5)+x-x
(2/3)*(6*x+30)-(5*(x+5))-x+x = 0
(2/3)*(6*x+30)-5*(x+5)-x+x = 0
2/3*(6*x+30)-5*(x+5)-x+x = 0
2/3*(6*x+30)-5*(x+5)-x+x = 0
x-x-x-5 = 0
x-2*x-5 = 0
-x-5 = 0
-x-5 = 0
-x-5 = 0 // + 5
-x = 5 // * -1
x = -5
x = -5
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