2/3(6x-10)=-3x+17

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Solution for 2/3(6x-10)=-3x+17 equation: 



2/3(6x-10)=-3x+17

We move all terms to the left:

2/3(6x-10)-(-3x+17)=0



Domain of the equation: 3(6x-10)!=0

x∈R



We get rid of parentheses

2/3(6x-10)+3x-17=0

We multiply all the terms by the denominator


3x*3(6x-10)-17*3(6x-10)+2=0

Wy multiply elements

9x^2(6-51x(6+2=0

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