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2/3(6x-12)=-17
We move all terms to the left:
2/3(6x-12)-(-17)=0
Domain of the equation: 3(6x-12)!=0We add all the numbers together, and all the variables
x∈R
2/3(6x-12)+17=0
We multiply all the terms by the denominator
17*3(6x-12)+2=0
Wy multiply elements
51x(6+2=0
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