2/3(6x-12)=8x-4-16

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Solution for 2/3(6x-12)=8x-4-16 equation: 



2/3(6x-12)=8x-4-16

We move all terms to the left:

2/3(6x-12)-(8x-4-16)=0



Domain of the equation: 3(6x-12)!=0

x∈R



We add all the numbers together, and all the variables

2/3(6x-12)-(8x-20)=0

We get rid of parentheses

2/3(6x-12)-8x+20=0

We multiply all the terms by the denominator


-8x*3(6x-12)+20*3(6x-12)+2=0

Wy multiply elements

-24x^2(6+60x(6+2=0

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