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2/3(6x-12)=8x-4-16
We move all terms to the left:
2/3(6x-12)-(8x-4-16)=0
Domain of the equation: 3(6x-12)!=0We add all the numbers together, and all the variables
x∈R
2/3(6x-12)-(8x-20)=0
We get rid of parentheses
2/3(6x-12)-8x+20=0
We multiply all the terms by the denominator
-8x*3(6x-12)+20*3(6x-12)+2=0
Wy multiply elements
-24x^2(6+60x(6+2=0
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