2/3(6x-12x)=4x+12

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Solution for 2/3(6x-12x)=4x+12 equation: 



2/3(6x-12x)=4x+12

We move all terms to the left:

2/3(6x-12x)-(4x+12)=0



Domain of the equation: 3(6x-12x)!=0

x∈R



We add all the numbers together, and all the variables

2/3(-6x)-(4x+12)=0

We get rid of parentheses

2/3(-6x)-4x-12=0

We multiply all the terms by the denominator


-4x*3(-6x)-12*3(-6x)+2=0

Wy multiply elements

-12x^2(--36x(-+2=0

We use the square of the difference formula

-12x^2(+36x(-2=0

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