2/3(6x-3)=3/5(20x+5)

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Solution for 2/3(6x-3)=3/5(20x+5) equation: 



2/3(6x-3)=3/5(20x+5)

We move all terms to the left:

2/3(6x-3)-(3/5(20x+5))=0



Domain of the equation: 3(6x-3)!=0

x∈R





Domain of the equation: 5(20x+5))!=0

x∈R



We calculate fractions


(10x2/(3(6x-3)*5(20x+5)))+(-9x6/(3(6x-3)*5(20x+5)))=0



We calculate terms in parentheses: +(10x2/(3(6x-3)*5(20x+5))), so:

10x2/(3(6x-3)*5(20x+5))

We multiply all the terms by the denominator


10x2

We add all the numbers together, and all the variables

10x^2

Back to the equation:

+(10x^2)





We calculate terms in parentheses: +(-9x6/(3(6x-3)*5(20x+5))), so:

-9x6/(3(6x-3)*5(20x+5))

We multiply all the terms by the denominator


-9x6

We add all the numbers together, and all the variables

-9x^6

We do not support expression: x^6

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