2/3(6x-9)+2x=1/3(9x)

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Solution for 2/3(6x-9)+2x=1/3(9x) equation:



2/3(6x-9)+2x=1/3(9x)
We move all terms to the left:
2/3(6x-9)+2x-(1/3(9x))=0
Domain of the equation: 3(6x-9)!=0
x∈R
Domain of the equation: 39x)!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
2/3(6x-9)+2x-(+1/39x)=0
We add all the numbers together, and all the variables
2x+2/3(6x-9)-(+1/39x)=0
We get rid of parentheses
2x+2/3(6x-9)-1/39x=0
We calculate fractions
2x+78x/(702x^2-1053x)+(-3x6/(702x^2-1053x)=0
We calculate terms in parentheses: +(-3x6/(702x^2-1053x), so:
-3x6/(702x^2-1053x
We multiply all the terms by the denominator
-3x6
We add all the numbers together, and all the variables
-3x^6
We do not support expression: x^6

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