2/3(6x-9)=1/5(10x+5)

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Solution for 2/3(6x-9)=1/5(10x+5) equation: 



2/3(6x-9)=1/5(10x+5)

We move all terms to the left:

2/3(6x-9)-(1/5(10x+5))=0



Domain of the equation: 3(6x-9)!=0

x∈R





Domain of the equation: 5(10x+5))!=0

x∈R



We calculate fractions


(10x1/(3(6x-9)*5(10x+5)))+(-3x6/(3(6x-9)*5(10x+5)))=0



We calculate terms in parentheses: +(10x1/(3(6x-9)*5(10x+5))), so:

10x1/(3(6x-9)*5(10x+5))

We multiply all the terms by the denominator


10x1

We add all the numbers together, and all the variables

10x

Back to the equation:

+(10x)





We calculate terms in parentheses: +(-3x6/(3(6x-9)*5(10x+5))), so:

-3x6/(3(6x-9)*5(10x+5))

We multiply all the terms by the denominator


-3x6

We add all the numbers together, and all the variables

-3x^6

We do not support expression: x^6

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