2/3(6x-9)=10x+28

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Solution for 2/3(6x-9)=10x+28 equation:



2/3(6x-9)=10x+28
We move all terms to the left:
2/3(6x-9)-(10x+28)=0
Domain of the equation: 3(6x-9)!=0
x∈R
We get rid of parentheses
2/3(6x-9)-10x-28=0
We multiply all the terms by the denominator
-10x*3(6x-9)-28*3(6x-9)+2=0
Wy multiply elements
-30x^2(6-84x(6+2=0

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