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(2/3)*(6*x-(9*y)) = 0
(2/3)*(6*x-9*y) = 0
2/3*(6*x-9*y) = 0
( 2/3 )
2/3 = 0
x belongs to the empty set
( 6*x-9*y )
6*x-9*y = 0 // + -9*y
6*x = -(-9*y) // : 6
x = (-(-9*y))/6
x = (3*y)/2
x = (3*y)/2
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