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(2/3)*(6*x-x) = (5/6)*x // - (5/6)*x
(2/3)*(6*x-x)-((5/6)*x) = 0
(2/3)*(6*x-x)+(-5/6)*x = 0
2/3*5*x+(-5*x)/6 = 0
(2/3*5*6*x)/6+(-5*x)/6 = 0
2/3*5*6*x-5*x = 0
15*x = 0
(15*x)/6 = 0
(15*x)/6 = 0 // * 6
15*x = 0
15*x = 0 // : 15
x = 0
x = 0
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