2/3(6y+12)+y=-17

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Solution for 2/3(6y+12)+y=-17 equation: 



2/3(6y+12)+y=-17

We move all terms to the left:

2/3(6y+12)+y-(-17)=0



Domain of the equation: 3(6y+12)!=0

y∈R



We add all the numbers together, and all the variables

y+2/3(6y+12)+17=0

We multiply all the terms by the denominator


y*3(6y+12)+17*3(6y+12)+2=0

Wy multiply elements

3y^2(6+51y(6+2=0

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