2/3(6z-9)+z=-18

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Solution for 2/3(6z-9)+z=-18 equation: 



2/3(6z-9)+z=-18

We move all terms to the left:

2/3(6z-9)+z-(-18)=0



Domain of the equation: 3(6z-9)!=0

z∈R



We add all the numbers together, and all the variables

z+2/3(6z-9)+18=0

We multiply all the terms by the denominator


z*3(6z-9)+18*3(6z-9)+2=0

Wy multiply elements

3z^2(6+54z(6+2=0

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