2/3(7/8+4x)-1/8=7/8

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Solution for 2/3(7/8+4x)-1/8=7/8 equation: 


x in (-oo:+oo)

(2/3)*(4*x+7/8)-(1/8) = 7/8 // - 7/8

(2/3)*(4*x+7/8)-(1/8)-(7/8) = 0

(2/3)*(4*x+7/8)-1/8-7/8 = 0

2/3*(4*x+7/8)-1/8-7/8 = 0

(2/3*8*(4*x+7/8))/8-1/8-7/8 = 0

2/3*8*(4*x+7/8)-7-1 = 0

64/3*x-7+11/3 = 0

64/3*x-10/3 = 0

(64/3*x-10/3)/8 = 0

(64/3*x-10/3)/8 = 0 // * 8

64/3*x-10/3 = 0

64/3*x-10/3 = 0 // + 10/3

64/3*x = 10/3 // : 64/3

x = 10/3/64/3

x = 5/32

x = 5/32

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