2/3(7x+5)=36

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Solution for 2/3(7x+5)=36 equation: 



2/3(7x+5)=36

We move all terms to the left:

2/3(7x+5)-(36)=0



Domain of the equation: 3(7x+5)!=0

x∈R



We multiply all the terms by the denominator


-36*3(7x+5)+2=0

Wy multiply elements

-108x(7+2=0

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