2/3(7x-4)+5=3

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Solution for 2/3(7x-4)+5=3 equation: 



2/3(7x-4)+5=3

We move all terms to the left:

2/3(7x-4)+5-(3)=0



Domain of the equation: 3(7x-4)!=0

x∈R



We add all the numbers together, and all the variables

2/3(7x-4)+2=0

We multiply all the terms by the denominator


2*3(7x-4)+2=0

Wy multiply elements

6x(7+2=0

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