If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x in (-oo:+oo)
(2/3)*(7*x-7) = 0
2/3*(7*x-7) = 0
( 2/3 )
2/3 = 0
x belongs to the empty set
( 7*x-7 )
7*x-7 = 0 // + 7
7*x = 7 // : 7
x = 7/7
x = 1
x = 1
| x/3,49=25 | | 27n=49 | | -6(-2-5x)=12 | | -2(2c-4)=.3(-12+24) | | r^6=64 | | x^4+10x^3+11x^2+14x+6=0 | | 5(m-12)=50 | | -10x-57=0 | | 13-14x+21=32 | | 32=2n-2n+5n | | n/8=7/9 | | 9.1x+8.31=-10.9x+7.63 | | -7(-4-4x)=364 | | 137-107= | | 6(2z-1)-4(z+8)=5(z+1) | | (2-3xy+9x^2-y^2)-(6y^2-3xy-4)= | | y-6=-2.5(x+4) | | x^2=20.25 | | 7x+7=-133-7x | | 3(2x-1)=2x+15 | | 1/3(-12c | | 8(2v-2)=22 | | 25x^2+5=16 | | (x+5)x=42 | | -2n-1=9 | | y-6.75=-1/4x | | 0=-16t^2+60t-6 | | -2w^2-3w+324=0 | | y-63/4=-1/4x | | 2x+9=64 | | -98=39.2t-4.9t^2 | | y-3=-5/6(x-5) |