2/3(9-6s)=(s+3)

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Solution for 2/3(9-6s)=(s+3) equation:



2/3(9-6s)=(s+3)
We move all terms to the left:
2/3(9-6s)-((s+3))=0
Domain of the equation: 3(9-6s)!=0
s∈R
We add all the numbers together, and all the variables
2/3(-6s+9)-((s+3))=0
We multiply all the terms by the denominator
-(((s+3)))*3(-6s+9)+2=0
We calculate terms in parentheses: -(((s+3)))*3(-6s+9), so:
((s+3)))*3(-6s+9
We add all the numbers together, and all the variables
-6s+((s+3)))*3(+9
Back to the equation:
-(-6s+((s+3)))*3(+9)
We add all the numbers together, and all the variables
-(-6s+((s+3)))*39+2=0
We move all terms containing s to the left, all other terms to the right
-(-6s+((s+3)))*39=-2

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