2/3(9b-27)36

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Solution for 2/3(9b-27)36 equation: 


b in (-oo:+oo)

(2/3)*(9*b-27)^36 = 0

2/3*(9*b-27)^36 = 0

( 2/3 )

2/3 = 0

b belongs to the empty set

( 9*b-27 )

9*b-27 = 0 // + 27

9*b = 27 // : 9

b = 27/9

b = 3

b in { 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3 }

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