2/3(9b-27)=35

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Solution for 2/3(9b-27)=35 equation: 



2/3(9b-27)=35

We move all terms to the left:

2/3(9b-27)-(35)=0



Domain of the equation: 3(9b-27)!=0

b∈R



We multiply all the terms by the denominator


-35*3(9b-27)+2=0

Wy multiply elements

-105b(9+2=0

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