2/3(9b-27)=80

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Solution for 2/3(9b-27)=80 equation: 


b in (-oo:+oo)

(2/3)*(9*b-27) = 80 // - 80

(2/3)*(9*b-27)-80 = 0

2/3*(9*b-27)-80 = 0

2/3*(9*b-27)-80 = 0

6*b-98 = 0

6*b-98 = 0

6*b-98 = 0 // + 98

6*b = 98 // : 6

b = 98/6

b = 49/3

b = 49/3

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