2/3(9b-2f)=36

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Solution for 2/3(9b-2f)=36 equation: 


x in (-oo:+oo)

(2/3)*(9*b-(2*f)) = 36 // - 36

(2/3)*(9*b-(2*f))-36 = 0

(2/3)*(9*b-2*f)-36 = 0

2/3*(9*b-2*f)-36 = 0

2/3*(9*b-2*f)-36 = 0

6*b-4/3*f-36 = 0

6*b-4/3*f-36 = 0

x belongs to the empty set

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