2/3(9k+10.5)=1/9(72k-117)

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Solution for 2/3(9k+10.5)=1/9(72k-117) equation: 



2/3(9k+10.5)=1/9(72k-117)

We move all terms to the left:

2/3(9k+10.5)-(1/9(72k-117))=0



Domain of the equation: 3(9k+10.5)!=0

k∈R





Domain of the equation: 9(72k-117))!=0

k∈R



We calculate fractions


(18k7/(3(9k+10.5)*9(72k-117)))+(-3k9/(3(9k+10.5)*9(72k-117)))=0



We calculate terms in parentheses: +(18k7/(3(9k+10.5)*9(72k-117))), so:

18k7/(3(9k+10.5)*9(72k-117))

We multiply all the terms by the denominator


18k7

We add all the numbers together, and all the variables

18k^7

We do not support ekpression: k^7

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