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2/3(9r-12)=6r
We move all terms to the left:
2/3(9r-12)-(6r)=0
Domain of the equation: 3(9r-12)!=0We add all the numbers together, and all the variables
r∈R
-6r+2/3(9r-12)=0
We multiply all the terms by the denominator
-6r*3(9r-12)+2=0
Wy multiply elements
-18r^2(9+2=0
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