2/3(9x+9)-15=-1/5(40x-15)

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Solution for 2/3(9x+9)-15=-1/5(40x-15) equation: 



2/3(9x+9)-15=-1/5(40x-15)

We move all terms to the left:

2/3(9x+9)-15-(-1/5(40x-15))=0



Domain of the equation: 3(9x+9)!=0

x∈R





Domain of the equation: 5(40x-15))!=0

x∈R



We calculate fractions


(10x4/(3(9x+9)*5(40x-15)))+(-(-3x9)/(3(9x+9)*5(40x-15)))-15=0



We calculate terms in parentheses: +(10x4/(3(9x+9)*5(40x-15))), so:

10x4/(3(9x+9)*5(40x-15))

We multiply all the terms by the denominator


10x4

We add all the numbers together, and all the variables

10x^4

We do not support expression: x^4

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