2/3(9x-12)+4x=1/2(4x+10)

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Solution for 2/3(9x-12)+4x=1/2(4x+10) equation: 



2/3(9x-12)+4x=1/2(4x+10)

We move all terms to the left:

2/3(9x-12)+4x-(1/2(4x+10))=0



Domain of the equation: 3(9x-12)!=0

x∈R





Domain of the equation: 2(4x+10))!=0

x∈R



We add all the numbers together, and all the variables

4x+2/3(9x-12)-(1/2(4x+10))=0

We calculate fractions


4x+(4x4/(3(9x-12)*2(4x+10)))+(-3x9/(3(9x-12)*2(4x+10)))=0



We calculate terms in parentheses: +(4x4/(3(9x-12)*2(4x+10))), so:

4x4/(3(9x-12)*2(4x+10))

We multiply all the terms by the denominator


4x4

We add all the numbers together, and all the variables

4x^4

We do not support expression: x^4

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