2/3(9x-27)=6x

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Solution for 2/3(9x-27)=6x equation:


x in (-oo:+oo)

(2/3)*(9*x-27) = 6*x // - 6*x

(2/3)*(9*x-27)-(6*x) = 0

(2/3)*(9*x-27)-6*x = 0

2/3*(9*x-27)-6*x = 0

2/3*(9*x-27)-6*x = 0

-18 = 0

-18 = 0

x belongs to the empty set

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