2/3(9x-3)=3(2x-1)

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Solution for 2/3(9x-3)=3(2x-1) equation: 


x in (-oo:+oo)

(2/3)*(9*x-3) = 3*(2*x-1) // - 3*(2*x-1)

(2/3)*(9*x-3)-(3*(2*x-1)) = 0

(2/3)*(9*x-3)-3*(2*x-1) = 0

2/3*(9*x-3)-3*(2*x-1) = 0

2/3*(9*x-3)-3*(2*x-1) = 0

1 = 0

1 = 0

1 = 0

x belongs to the empty set

x belongs to the empty set

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