2/3(9x-3)=3(2x-1/2)

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Solution for 2/3(9x-3)=3(2x-1/2) equation:


x in (-oo:+oo)

(2/3)*(9*x-3) = 3*(2*x-(1/2)) // - 3*(2*x-(1/2))

(2/3)*(9*x-3)-(3*(2*x-(1/2))) = 0

(2/3)*(9*x-3)-3*(2*x-1/2) = 0

2/3*(9*x-3)-3*(2*x-1/2) = 0

2/3*(9*x-3)-3*(2*x-1/2) = 0

-1/2 = 0

-1/2 = 0

-1/2 = 0 // * 2

-1 = 0

-1 = 0

x belongs to the empty set

x belongs to the empty set

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