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2/3(9x-3)=5/4(4x+8)
We move all terms to the left:
2/3(9x-3)-(5/4(4x+8))=0
Domain of the equation: 3(9x-3)!=0
x∈R
Domain of the equation: 4(4x+8))!=0We calculate fractions
x∈R
(8x4/(3(9x-3)*4(4x+8)))+(-15x9/(3(9x-3)*4(4x+8)))=0
We calculate terms in parentheses: +(8x4/(3(9x-3)*4(4x+8))), so:
8x4/(3(9x-3)*4(4x+8))
We multiply all the terms by the denominator
8x4
We add all the numbers together, and all the variables
8x^4
We do not support expression: x^4
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