2/3(a+6)+3/4(2a+1)+13/12=0

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Solution for 2/3(a+6)+3/4(2a+1)+13/12=0 equation: 



2/3(a+6)+3/4(2a+1)+13/12=0



Domain of the equation: 3(a+6)!=0

a∈R





Domain of the equation: 4(2a+1)!=0

a∈R



We calculate fractions


(96a2/(3(a+6)*4(2a+1)*12)+(108aa/(3(a+6)*4(2a+1)*12)+(156a^2a/(3(a+6)*4(2a+1)*12)=0



We calculate terms in parentheses: +(96a2/(3(a+6)*4(2a+1)*12)+(108aa/(3(a+6)*4(2a+1)*12)+(156a^2a/(3(a+6)*4(2a+1)*12), so:

96a2/(3(a+6)*4(2a+1)*12)+(108aa/(3(a+6)*4(2a+1)*12)+(156a^2a/(3(a+6)*4(2a+1)*12

We can not solve this equation

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