2/3(a-6)=1/4(a+8)

Solution for 2/3(a-6)=1/4(a+8) equation:

2/3(a-6)=1/4(a+8)

We move all terms to the left:

2/3(a-6)-(1/4(a+8))=0


Domain of the equation: 3(a-6)!=0

a∈R



Domain of the equation: 4(a+8))!=0

a∈R


We calculate fractions


(8aa/(3(a-6)*4(a+8)))+(-3aa/(3(a-6)*4(a+8)))=0


We calculate terms in parentheses: +(8aa/(3(a-6)*4(a+8))), so:

8aa/(3(a-6)*4(a+8))

We multiply all the terms by the denominator


8aa

Back to the equation:

+(8aa)



We calculate terms in parentheses: +(-3aa/(3(a-6)*4(a+8))), so:

-3aa/(3(a-6)*4(a+8))

We multiply all the terms by the denominator


-3aa

Back to the equation:

+(-3aa)


We get rid of parentheses

8aa-3aa=0