2/3(c+9)=39

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Solution for 2/3(c+9)=39 equation:



2/3(c+9)=39
We move all terms to the left:
2/3(c+9)-(39)=0
Domain of the equation: 3(c+9)!=0
c∈R
We multiply all the terms by the denominator
-39*3(c+9)+2=0
Wy multiply elements
-117c(c+2=0

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